I am not experienced with FireCalc so this may be a dumb question.* Can the floor be redefined, such that a "failure" might be for example a decline to 1/2 the starting portfolio value?
I ran the defaults: $750,000 portfolio, $30,000 pa withdrawal, etc. It says "6 failures" for a success rate of 94.3%, or conversely a failure rate of 5.7%.
But I think I would not be happy with missing a tap-out by a few bucks. Also, I am puzzled by this:
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And here is how your portfolio would have ended up in each of the 106 cycles. The range was $-300,739 to $4,259,606, with an average of $1,284,723. (Note: values are in terms of the dollars as of the beginning of the retirement period for each cycle.)
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How did I get to (-$300,739) on the least successful path?
Does this mean that I had some non-zero amount at the start of the failure year, and suffered a catastrophic loss in that year?
Also, I am puzzled by this statement
Quote:
(Note: values are in terms of the dollars as of the beginning of the retirement period for each cycle.)
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Does this mean That all ouputs that are money amounts are expressed at the same index value as the starting portfolio and the starting withdrawal? So that if I were to run the default today, I would assume that all money outputs are in today's dollar?
Thanks for any help.
Ha